These questions are from TCS new test pattern for 2014 batch. There are few repetitions from the previous year's question paper .Here are some of the TCS questions and solution with Explanation.
1. P is thirty percentage of Q, Q is twenty percentage of N. M is fifty percentage of N, Find the value of P/N ?
Ans. .06
Explanation: P = .3Q
Q = .2N
M = .5N
P = (.3*.2)N
P/N = .06
2. If twenty four men and sixteen women work on a day, the total wages to be paid is 11,600. If twelve men and thirty seven women work on a day, the total wages to be paid remains the same. What is the wages paid to a man for a day’s work?
Ans. 350
Explanation: Since the wages paid are equal, total work done by both the groups should also be equal.
Equating the total work done in terms of men days and women days.
24m+16w=12m+37w - (1)
12m=21w (or) 4m=7w
Substituting w=4m/7 in eqn 1 we get
24m + 16w = 24w + 16(4m/7)
= (168m+64m)/7
= The total amount paid for 232m/7 = 11600
For each men = (11600*7)/232=350.
3. A takes 2 hours to make a publication. B takes 10 hours to make a publication. Find the time
taken by them to make two publications, working independently?
Ans. 10
Explanation: A can complete a publication in 2 hours and B in 10 hours and so the maximum time taken by both working independently to complete 2 publications will be 10 hours.
4. If all the numbers between 11 and 100 are written on a piece of paper. How many times will
the number 4 be used?
Ans. 19
Explanation: 14,24,34,44,54,64,74,84,94,40,41,42,43,44,45,46,47,48,49
Therefor there are 19 times the number 4 can be used between 11-100.
5. In a school , sixty percent of the students are girls and thirty five percent of the girl s are poor. If a student is randomly selected, what is the probability of selecting a poor girl student?
Ans. 21%
Explanation: Let the number of the students be X.
Therefore poor girl students = .35*.65*X
The probability of selecting poor girl is given by
= (.35*.65)*X
(100/100)*X =21%
6. Two beakers are on the table. The capacity of the first beaker is x litres and that of the second beaker is 2x litres. Two thirds of the first beaker and one fourth of the second beaker is filled with wine. The remaining space is filled with water. If the content in both the beakers are mixed in a large beaker of volume 3x litres, what is the proportion of wine in the beaker?
Ans. 7/6
7.Three non negative numbers, X, Y and Z are such that the mean is M and the median is 5. If M is 10 more than the smallest number and 15 less than the biggest number, find the va lue of X+Y+Z.
Ans. 30
Explanation: (X+Y+Z)3 = M (or) X +Y +Z +3M
Let Y be the middle value, then Y=5
X+Z=3M-5
X=M-10;
Z=M+15;
M-10+M+15=3M-5
M=10
X=0; Y=5; Z=25
8. From 5 men and 11 women, in how many ways can a panel of 11 be formed such that the number of men is not more than 3?
Ans: 2266
Explanation: (5C3*11C8)+(5C2*11C9)+(5C1*11C10)+(11C11) = 2266
9. After 6 years Raju’s father will be twice that of his age and two years ago, his mothers age was twice of that of Raju’s age. What is the sum of Raju’s parent’s age?
Ans. 4 more than four times Raju’s age
Explanation: F+6=2(R+6)
F= 2R+6
M-2=2(R-2)
M= 2R-2
Therefore the sum of Raju’s Parent’s age is
F+M=2R+6+2R-2
F+M=4R+4
4 more than four times Raju’s age
10. The cost price of a cow and a horse is Rs 3 lakhs. The cow is sold at 20% profit and the horse is sold at 10% loss. Overall gain is Rs 4200. What is the cost price of the cow?
Ans. 240000
Explanation: C+H=300000 -----eqution 1
1.20C+.90H=304200 --------equation 2
On equating 1 and 2 we get
C= Rs. 240000 and H= Rs.60000
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