Monday 10 February 2014

TCS sample placement paper uploaded by TCS

Monday, February 10, 2014

TCS had uploaded a sample paper in their Portal to give you the idea of type of question will be asked and to become familiar with their User Interface.I am providing the sample question with their solution. You will clearly get an idea about the difficulty level.

1. If ‘m’ is an odd integer and ‘n’ an even integer, which of the following is definitely odd?

Ans. m+n

Explanation: You just remember the following odd    odd = even; even    even = even; even    odd = odd. Also odd x odd = odd; even x even = even; even x odd = even.

2. If 3y + x > 2 and x + 2y  3, What can be said about the value of y?

Ans. y>-1

Explanation: Multiply the second equation with -1 then it will become - x - 2y >= - 3.  Add the equations.  You
will get y > -1.

3. There are 20 balls which are red, blue or green.  If 7 balls are green and the sum of red balls and green balls is less than 13, at most how many red balls are there?

Ans. 5

Explanation: Given R + B + G = 20; G = 7; and R + G < 13.  Substituting G = 7 in the last equation, We get R < 6.  So maximum value of R = 5.

4. All faces of a cube with an eight - meter edge are painted red.  If the cube is cut into smaller cubes with a two - meter edge, how many of the two meter cubes have paint on exactly one face?

Ans: 48

Explanation: If there are n cubes lie on an edge, then total number of cubes with one side painting is given by 6 X  (n-2)edge. Hence answer = 24.

5. Two cyclists begin training on an oval racecourse at the same time.The professional cyclist completes each lap in 4 minutes; the novice takes 6 minutes to complete each lap.   How many minutes after the start will both cyclists pass at exactly in the 15 the lap,at the same spot where they began to cycle?

Ans. 165

Explanation: L.C.M for 4  & 6 is 12 so first meet is 12.and 15 th lap is 15 * 12 =165

6. Arun, Akash, Amir and Aswanth go for a picnic.   When Arun stands on a weighing machine, Akash also climbs  on,  and  the  weight  shown  was  132  kg.   When  Akash  stands,  Amir  also climbs  on,  and  the machine shows 130 kg.  Similarly the weight of Amir and Aswanth is found as 102 kg and that of Akash and Aswanth is 116 kg.  What is Aswanth’s weight?

Ans. 44 kg

Explanation: Given A + B = 132; B + C = 130; C + D = 102, B + D = 116
Eliminate B from 2nd and 4th equation and solving this equation and 3rd we get D value as 44.

7. Roy is now 4 years older than Erik and half of that amount older than Iris. If in 2 years, roy will be twice as old as Erik, then in 2 years what would be Roy's age multiplied by Iris's age?

Ans. 48

Explanation: R  =4+ E
R =2 + I
R+2 = 2(E+2 )
Solving all the above equations we get
R= 6,E= 2,I =4 so after 2 yrs it is R=8 and I =6,which is 48.

8.The telephone company wants to add an area code composed of 2 letters to every phone number. In order  to  do  so,  the  company  chose  a  special  sign  language  containing  124  different  signs.  If  the company used 122 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 124 signs?

Ans: 492

Explanation: The phone company already created 122*122 area codes, now it can create 124*124. 1242-1222 =(124+122)(124-122) = 246*2 = 492 additional codes.

9. A bakery opened yesterday with its daily supply of 40 dozen rolls. Half of the rolls were sold by noon and 80 % of the remaining rolls were sold between noon and closing time. How many dozen rolls had not been sold when the bakery closed yesterday?

Ans. 4

Explanation: 4 rolls were not sold.Because half of them were sold by noon.So 20 rolls remain, and then 20% were not sold. So 20% of the 20 rolls is 4.

10. A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead and yellow bead. If the necklace begins with a red bead and ends with a white bead, then N could be:

Ans: 68

Explanation: R G W B Y is the bead pattern and it repeats.
Bead want to end with White.
So, the 3rd, 8th, 13th, 18th... beads will be W.
this can be expressed as 5n+3,where n is an integer.(counting no of white bead)
Test each of the answer choices to determine which is multiple of 5 plus a value of 3.Of the options ,only 68=5(13)+3 can be written in the form 5n+3.
So,the answer is 68.

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2 comments:

  1. in 9th que they mentnd 40 dozen rolls which means 40*12=480 rolls
    till noon 1/2(480)=240 rolls are sold
    aftr noon till closing time 80% of 240 i.e., 80\100(240)=192 rolls are sold
    so, remaining rolls which are nt sold are 240-192=48

    ReplyDelete
    Replies
    1. You have to give the answer in dozen. So, the answer will be 4 dozen, which is equal to 48.

      Delete

 

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