Friday 21 February 2014

IBM Placement Paper 2014 (2)

Friday, February 21, 2014

This set of Placement paper is collected from on-campus recruitment drive for the session (2013-2014). Try to practice each question from this set as IBM repeats its questions. You will surely get some 4 to 5 questions common in your Online Test. If you are in the lucky side, even you can expect more common questions. We are posting the exact questions that are asked in IBM on-campus recruitment.


Here are some questions from number series.

1)  2, 1, 2, 3, 8, 0, 1, 9, 1, 2, ?

Ans. 1

Explanation: 21=2
23=8
80=1
19=1
12=1.
 
2) 7, 9, 11, 6, 11, 8, 5, 13, 5, 4, 15, ?

Ans. 2

Explanation: Divide the series in set of 3
1st set-  7  9 11
2nd set- 6 11 8
3rd set-  5 13 5
4th set-  4 15 ?
1st column- 7,6,5,4  (Subtract  1)
2st column- 9,11,13,15 ( Add 2 )
3st column- 11,8,5,? (Subtract 3)
Therefore, the missing term is 5 - 3 = 2


3) 2/3, 5/3, 19/6, 31/6, 23/3, 32/3, 84/6, ?

Ans. 108/6

Explanation: 2/3+1=5/3
19/6+2=31/6
23/3+3=32/3
84/6+4=108/6

4)  9, 12, 4, 8, 12, 15, 5, 9, 3, 6, 2, 6, 6, 9, ?

Ans. 3

Explanation: Divide the series into set of 4.
1st set-  9,12,4,8
2nd set- 12,15,5,9
3rd set- 3,6,2,6
4th set- 6,9, ?
Rules applied in each set
9+3=12, 12/3=4, 4+4=8
12+3=15, 15/3=5, 5+4=9
3+3=6, 6/3=2, 2+4=6
Therefore, 6+3=9, 9/3=3

5) 2, 3, 10, 15,26, ?

Ans.35

Explanation: 2*2-1=3
3*3+1=10
4*4-1=15
5*5+1=26
6*6-1=35

6) 507,169,248,62,36,12,168,42,168, ?

Ans. 56

Explanation: 507/3=169
248/4=62
36/3=12
168/4=42
168/3= 56

7)  4, 3, 144, 1.5, 2, 9, 5, 0.3, 2.25, 3.2, 2,?

Ans. 40.96

Explanation: 4 * 3= 122= 144
1.5 * 2 =32=9
5 * 0.3 = 1.5 2 = 2.25
Therefore, 3.2*2=6.42=40.96

8) 49, 7, 98, 16, 4, 48, 9, 36, 25, 5,?

Ans.125

Explanation: 72=49,49*2=98
42=16,16*3=48
32=9 ,9*4=36
52=25,25*5=125

9) 96, 64, 128,192, 128, 256, 288, 192, ?

Ans.384

Explanation: Divide the series in set of 3.
1st set- 96,64,128
2nd set-192,128,256
3rd set- 288,192,?

Take 1st column-96 * 2=192, 96*3=288
2nd column- 64 * 2 =128, 64*3= 192
Therefore, 3rd column =128*2= 256, 128* 3= 384

10) 11 ,8 ,17 ,14 ,23 ,24 ,31 ,32,?

Ans. 39

Explanation: First divide the series
11 8 17- Difference bet. 2nd and 1st term is 3 and 3rd and 2nd term is 9
17 14 23 - Difference bet. 2nd and 1st term is 3 and 3rd and 2nd term is 9
23 24 31-Difference bet. 2nd and 1st term is  and 3rd and 2nd term is 7
Therefore, applying same rules we get 31 32 39

11) 3, 2, 1, 4, 5, 4, 5, 1, 0, 6, 3, ?

Ans. 2

Explanation:3+2-1=4
4+5-4=5
5+1-0=6
6+3-x=7 Therefore, x=2

12) 3, 7, 10, 8, 4, 12, 0, 5, 5, 3, 2, 5,?

Ans.3

Explanation: Divide the series in set of 3
1st set- 1,9,0  (1+9+0=10 )
2nd set- 2,7,1 (2+7+1=10)
3rd set- 3,5,2  (3+5+2=10)
4th set  4,3,?   Therefore, 4+3+x =10 , x=3.

13) 49, 7, 98, 16, 4, 48, 9, 3, 36, 25, 5, ?

Ans. 125

Explanation: Divide the series in set of 3
1st set- 49,7,98     logic-7*7 = 49 , 49*2=98
2nd set- 16,4,48   logic- 4*4=16 ,16*3=48
3rd set- 9,3,36      logic-3*3 = 9 , 9*4=36
4th set- 25,5,?      Therefore, 5*5=25 and 25*5=125


14) 5, 6, 6, 5, 6.5, 8, 7, 9.5, ?

Ans. 7.5

Explanation: There sub series inside the series
Take the alternate numbers to make the series
1st series- 5, 6.5, 8, 9.5 (Add  1.5)
2nd series-6, 6.5,7, ?(Add 0.5)

Therefore, the next term is 7+.5= 7.5

15)  8,16,3,27,4,8,7,19,2,0,7, ?

Ans. 9

Explanation: Divide the series in a set of 4
1st set-8,16,3,27   Logic-8+16+3=27
2nd set- 4,8,7,19   Logic-4+8+7=19
3rd set- 2,0,7,?      Therefore, 2+0+7=9


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