IBM Placement paper Set-1

This set of questions are collected from IBM on-campus recruitment (2013-14). In this set of questions we are only covering the general aptitude part. We will be posting the number series questions soon.

Round 1: Online Aptitude Test
No. of Question:  36     (18 questions on number series + 18 Aptitude question)
Time: 81 minute  (2:15 minute for each question)
Time allocated to each question: 2:15 minute

Here are some questions that are asked in aptitude test.

1. A software company has 630 employees of whom 80 percent are software engineers and 20 percent are sales representatives. To obtain a 25 percent sales representative proportion, how many additional employees should be added to the sales staff?

A. 157
B. 125
C. 31
D. 42
E. 33

Ans. 42

Explanation: Total no. of employee = 630
No. of Software engineers = 80 % of 630 = 504
No. of sales staffs = 20% of 630 = 126
Now, we have to make the percent sales staff to 25 % .
Let X no of sales staff will be added to make it 25 % of the total employees.
Therefore, (126+ x)/(630+x)=25/100
504 + 4x= 630 +x
3x= 126
x=42

2. A company brought twice as many small envelopes as large envelopes. It used up 5/15 of the small envelopes and 4/6 of the large envelopes. What fraction of the total number was left unused?

A. 4/9
B. 1/3
C. 5/9
D. 4/3
E. 2/3

Ans. 5/9

Explanation: Let the no. of large envelopes = x
Therefore no. of small envelopes = 2x.
No. of unused small envelopes = (1- 5/15)*2x = (10/15)* 2x=(4/3)x.
No of unused large envelopes = (1-4/6)*x = (2/6)*x = (1/3)x.
Total fraction of unused envelopes is = (((1/3)x) + ((4/3)x) /3x ) = 5/9

3. A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective?

A. 4/19
B. 7/19
C. 12/19
D. 21/95

Ans. 7/19

Explanation: Probability that none is defective out of two bulbs = (¹⁶c₂ / ²⁰c₂)=12/19.
Therefore the prob. that at least one is  defective is = 1-(12/19)=7/19

4. In 1978, a kg of paper was sold at Rs25/-. If the paper rate increases at 1.5% more than inflation rate which is of 6.5% a year, then what will be the cost of a kg of paper after 2 years?

A) 29.12
B. 29.72
C. 30.12
D. 32.65
E. none of these

Ans. 29.72

Explanation: Inflation Rate = 6.5%
Paper rate is 1.5% more than 6.5% = 1.5% +6.5% =8%
Therefore , the cost of paper after 2 year = 25 (1 +  8/100)²=25(1.08)²=29.16

5. On her first week on the job, a work station operator processed a batch of documents. On her second week, she processed 2 times as many, and on her third week she processed 15200 documents. If she processed a total of 34100 documents in the 3 weeks, how many documents did she process in her first week.

A. 4200
B. 10133
C. 5066
D. 9450
E. 6300

Ans. 6300

Explanation: Let the work station operator processed X documents in first week.
Then it processed 2x document in second week.
Third week it processed 15200 documents. (Given)
Therefore , X + 2X + 15200 = 34100
3X =18900
X= 6300

6. In a company, 60% are men and 40% are women.  Out of which 80% of men and 60% of women are in are senior citizen. How much percent of employees are senior citizen?

Ans. 72%

Explanation: 60% are men, of which 80% are senior citizen.
Therefore, percent of men senior citizen = (60/100)*(80/100)=48/100
Now 40% are women, of which 60% are senior citizen.
Therefore, percent of women senior citizen = (40/10)*(60/10)=24/100
Total percent  of senior citizen is (48/100) +(24/100)= (72/100)=72%

7. A television manufacture makes 7 different model sets in 5 screen sizes and 2 different model sets in 3 screen sizes. How many television units are required for a store to display each type of TV?

A. 39
B. 35
C. 13
D. 41
E. 9

Explanation: For the first  set - 7 x 5 =35
For the second set – 2 x 3 =6
Therefore 35 + 6 = 41

 8. Four dice are rolled simultaneously. What is the number of possible outcomes in which at least one of the die shows 6?

Ans. 671

Explanation: Total no. of outcomes when 4 dices are thrown = 6⁴ =1296
Total no. of outcomes, where no dice result is 5 = 5⁴ = 625
Therefore, total no. of outcomes in which at least one dice result is 6 = 1296-635= 671.

In our upcoming post, we will cover the number series questions from recent IBM placement papers. Soon we are coming up with huge collection of latest Placement papers and Interview Experience.
   

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